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Apply the formula: $\frac{d}{dx}\left(a^b\right)$$=y=a^b$, where $d/dx=\frac{d}{dx}$, $a=\mathrm{cosh}\left(x\right)$, $b=\sqrt{x}$, $a^b=\mathrm{cosh}\left(x\right)^{\left(\sqrt{x}\right)}$ and $d/dx?a^b=\frac{d}{dx}\left(\mathrm{cosh}\left(x\right)^{\left(\sqrt{x}\right)}\right)$
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$y=\mathrm{cosh}\left(x\right)^{\left(\sqrt{x}\right)}$
Learn how to solve problems step by step online. d/dx(cosh(x)^x^(1/2)). Apply the formula: \frac{d}{dx}\left(a^b\right)=y=a^b, where d/dx=\frac{d}{dx}, a=\mathrm{cosh}\left(x\right), b=\sqrt{x}, a^b=\mathrm{cosh}\left(x\right)^{\left(\sqrt{x}\right)} and d/dx?a^b=\frac{d}{dx}\left(\mathrm{cosh}\left(x\right)^{\left(\sqrt{x}\right)}\right). Apply the formula: y=a^b\to \ln\left(y\right)=\ln\left(a^b\right), where a=\mathrm{cosh}\left(x\right) and b=\sqrt{x}. Apply the formula: \ln\left(x^a\right)=a\ln\left(x\right), where a=\sqrt{x} and x=\mathrm{cosh}\left(x\right). Apply the formula: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), where x=\sqrt{x}\ln\left(\mathrm{cosh}\left(x\right)\right).
