Exercice
$\frac{7x^2-3x^4+1}{x-1}$
Solution étape par étape
1
Diviser $7x^2-3x^4+1$ par $x-1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-1;}{-3x^{3}-3x^{2}+4x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-1\overline{\smash{)}-3x^{4}\phantom{-;x^n}+7x^{2}\phantom{-;x^n}+1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-1;}\underline{\phantom{;}3x^{4}-3x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}3x^{4}-3x^{3};}-3x^{3}+7x^{2}\phantom{-;x^n}+1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n;}\underline{\phantom{;}3x^{3}-3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{3}-3x^{2}-;x^n;}\phantom{;}4x^{2}\phantom{-;x^n}+1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n;}\underline{-4x^{2}+4x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-4x^{2}+4x\phantom{;}-;x^n-;x^n;}\phantom{;}4x\phantom{;}+1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-1-;x^n-;x^n-;x^n;}\underline{-4x\phantom{;}+4\phantom{;}\phantom{;}}\\\phantom{;;;-4x\phantom{;}+4\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}5\phantom{;}\phantom{;}\\\end{array}$
$-3x^{3}-3x^{2}+4x+4+\frac{5}{x-1}$
Réponse finale au problème
$-3x^{3}-3x^{2}+4x+4+\frac{5}{x-1}$