Exercice
$\frac{2x^3-5x^2-23x-4}{-x+5}$
Solution étape par étape
1
Diviser $2x^3-5x^2-23x-4$ par $-x+5$
$\begin{array}{l}\phantom{-x\phantom{;}+5;}{-2x^{2}-5x\phantom{;}-2\phantom{;}\phantom{;}}\\-x\phantom{;}+5\overline{\smash{)}\phantom{;}2x^{3}-5x^{2}-23x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{-x\phantom{;}+5;}\underline{-2x^{3}+10x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{3}+10x^{2};}\phantom{;}5x^{2}-23x\phantom{;}-4\phantom{;}\phantom{;}\\\phantom{-x\phantom{;}+5-;x^n;}\underline{-5x^{2}+25x\phantom{;}\phantom{-;x^n}}\\\phantom{;-5x^{2}+25x\phantom{;}-;x^n;}\phantom{;}2x\phantom{;}-4\phantom{;}\phantom{;}\\\phantom{-x\phantom{;}+5-;x^n-;x^n;}\underline{-2x\phantom{;}+10\phantom{;}\phantom{;}}\\\phantom{;;-2x\phantom{;}+10\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}6\phantom{;}\phantom{;}\\\end{array}$
$-2x^{2}-5x-2+\frac{6}{-x+5}$
Réponse finale au problème
$-2x^{2}-5x-2+\frac{6}{-x+5}$