Exercice
$\frac{2x^3+9x^2+x-12}{2x+3}$
Solution étape par étape
1
Diviser $2x^3+9x^2+x-12$ par $2x+3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+3;}{\phantom{;}x^{2}+3x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+3\overline{\smash{)}\phantom{;}2x^{3}+9x^{2}+x\phantom{;}-12\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+3;}\underline{-2x^{3}-3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{3}-3x^{2};}\phantom{;}6x^{2}+x\phantom{;}-12\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n;}\underline{-6x^{2}-9x\phantom{;}\phantom{-;x^n}}\\\phantom{;-6x^{2}-9x\phantom{;}-;x^n;}-8x\phantom{;}-12\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n-;x^n;}\underline{\phantom{;}8x\phantom{;}+12\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}8x\phantom{;}+12\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Réponse finale au problème
$x^{2}+3x-4$