Exercice
$\frac{2x^3+6x^2-3x-1}{x+3}$
Solution étape par étape
1
Diviser $2x^3+6x^2-3x-1$ par $x+3$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+3;}{\phantom{;}2x^{2}\phantom{-;x^n}-3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+3\overline{\smash{)}\phantom{;}2x^{3}+6x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+3;}\underline{-2x^{3}-6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{3}-6x^{2};}-3x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+3-;x^n;}\underline{\phantom{;}3x\phantom{;}+9\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}3x\phantom{;}+9\phantom{;}\phantom{;}-;x^n;}\phantom{;}8\phantom{;}\phantom{;}\\\end{array}$
$2x^{2}-3+\frac{8}{x+3}$
Réponse finale au problème
$2x^{2}-3+\frac{8}{x+3}$