Exercice
$\frac{1+m^5}{1-m}$
Solution étape par étape
1
Diviser $1+m^5$ par $1-m$
$\begin{array}{l}\phantom{-m\phantom{;}+1;}{-m^{4}-m^{3}-m^{2}-m\phantom{;}-1\phantom{;}\phantom{;}}\\-m\phantom{;}+1\overline{\smash{)}\phantom{;}m^{5}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}+1\phantom{;}\phantom{;}}\\\phantom{-m\phantom{;}+1;}\underline{-m^{5}+m^{4}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-m^{5}+m^{4};}\phantom{;}m^{4}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}+1\phantom{;}\phantom{;}\\\phantom{-m\phantom{;}+1-;x^n;}\underline{-m^{4}+m^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-m^{4}+m^{3}-;x^n;}\phantom{;}m^{3}\phantom{-;x^n}\phantom{-;x^n}+1\phantom{;}\phantom{;}\\\phantom{-m\phantom{;}+1-;x^n-;x^n;}\underline{-m^{3}+m^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;;-m^{3}+m^{2}-;x^n-;x^n;}\phantom{;}m^{2}\phantom{-;x^n}+1\phantom{;}\phantom{;}\\\phantom{-m\phantom{;}+1-;x^n-;x^n-;x^n;}\underline{-m^{2}+m\phantom{;}\phantom{-;x^n}}\\\phantom{;;;-m^{2}+m\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}m\phantom{;}+1\phantom{;}\phantom{;}\\\phantom{-m\phantom{;}+1-;x^n-;x^n-;x^n-;x^n;}\underline{-m\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;;;;-m\phantom{;}+1\phantom{;}\phantom{;}-;x^n-;x^n-;x^n-;x^n;}\phantom{;}2\phantom{;}\phantom{;}\\\end{array}$
$-m^{4}-m^{3}-m^{2}-m-1+\frac{2}{1-m}$
Réponse finale au problème
$-m^{4}-m^{3}-m^{2}-m-1+\frac{2}{1-m}$