Exercice
$\frac{-x^3+12x+9}{x-4}$
Solution étape par étape
1
Diviser $-x^3+12x+9$ par $x-4$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-4;}{-x^{2}-4x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-4\overline{\smash{)}-x^{3}\phantom{-;x^n}+12x\phantom{;}+9\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-4;}\underline{\phantom{;}x^{3}-4x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}x^{3}-4x^{2};}-4x^{2}+12x\phantom{;}+9\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-4-;x^n;}\underline{\phantom{;}4x^{2}-16x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}4x^{2}-16x\phantom{;}-;x^n;}-4x\phantom{;}+9\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-4-;x^n-;x^n;}\underline{\phantom{;}4x\phantom{;}-16\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}4x\phantom{;}-16\phantom{;}\phantom{;}-;x^n-;x^n;}-7\phantom{;}\phantom{;}\\\end{array}$
$-x^{2}-4x-4+\frac{-7}{x-4}$
Réponse finale au problème
$-x^{2}-4x-4+\frac{-7}{x-4}$