Final answer to the problem
$\frac{\sec\left(x\right)}{\sin\left(x\right)}\sin\left(x\right)^2$
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1
Applying the trigonometric identity: $1-\cos\left(\theta \right)^2 = \sin\left(\theta \right)^2$
$\frac{\sec\left(x\right)}{\sin\left(x\right)}\sin\left(x\right)^2$
Why is 1 - cos(x)^2 = sin(x)^2 ?
Final answer to the problem
$\frac{\sec\left(x\right)}{\sin\left(x\right)}\sin\left(x\right)^2$
