Exercice
$\frac{\left(x^3+x^2\right)-0.144}{x-\left(-0.6\right)}$
Solution étape par étape
1
Diviser $x^3+x^2-0.144$ par $x+0.6$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+0.6;}{\phantom{;}x^{2}+0.4x\phantom{;}-0.24\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+0.6\overline{\smash{)}\phantom{;}x^{3}+x^{2}\phantom{-;x^n}-0.144\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+0.6;}\underline{-x^{3}-0.6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-x^{3}-0.6x^{2};}\phantom{;}0.4x^{2}\phantom{-;x^n}-0.144\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+0.6-;x^n;}\underline{-0.4x^{2}-0.24x\phantom{;}\phantom{-;x^n}}\\\phantom{;-0.4x^{2}-0.24x\phantom{;}-;x^n;}-0.24x\phantom{;}-0.144\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+0.6-;x^n-;x^n;}\underline{\phantom{;}0.24x\phantom{;}+0.144\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}0.24x\phantom{;}+0.144\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Réponse finale au problème
$x^{2}+0.4x-0.24$