Exercice
$\frac{\left(2x^3-7x^2-4\right)}{2x-3}$
Solution étape par étape
1
Diviser $2x^3-7x^2-4$ par $2x-3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-3;}{\phantom{;}x^{2}-2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-3\overline{\smash{)}\phantom{;}2x^{3}-7x^{2}\phantom{-;x^n}-4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-3;}\underline{-2x^{3}+3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{3}+3x^{2};}-4x^{2}\phantom{-;x^n}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-3-;x^n;}\underline{\phantom{;}4x^{2}-6x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}4x^{2}-6x\phantom{;}-;x^n;}-6x\phantom{;}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-3-;x^n-;x^n;}\underline{\phantom{;}6x\phantom{;}-9\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}6x\phantom{;}-9\phantom{;}\phantom{;}-;x^n-;x^n;}-13\phantom{;}\phantom{;}\\\end{array}$
$x^{2}-2x-3+\frac{-13}{2x-3}$
Réponse finale au problème
$x^{2}-2x-3+\frac{-13}{2x-3}$