Exercice
$\frac{\left(2x^2-8x-1\right)}{x+4}$
Solution étape par étape
1
Diviser $2x^2-8x-1$ par $x+4$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+4;}{\phantom{;}2x\phantom{;}-16\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+4\overline{\smash{)}\phantom{;}2x^{2}-8x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+4;}\underline{-2x^{2}-8x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{2}-8x\phantom{;};}-16x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+4-;x^n;}\underline{\phantom{;}16x\phantom{;}+64\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}16x\phantom{;}+64\phantom{;}\phantom{;}-;x^n;}\phantom{;}63\phantom{;}\phantom{;}\\\end{array}$
$2x-16+\frac{63}{x+4}$
Réponse finale au problème
$2x-16+\frac{63}{x+4}$