Exercice
$\frac{\left(2x^2-11x+20\right)}{2x+3}$
Solution étape par étape
1
Diviser $2x^2-11x+20$ par $2x+3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+3;}{\phantom{;}x\phantom{;}-7\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+3\overline{\smash{)}\phantom{;}2x^{2}-11x\phantom{;}+20\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+3;}\underline{-2x^{2}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{2}-3x\phantom{;};}-14x\phantom{;}+20\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n;}\underline{\phantom{;}14x\phantom{;}+21\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}14x\phantom{;}+21\phantom{;}\phantom{;}-;x^n;}\phantom{;}41\phantom{;}\phantom{;}\\\end{array}$
$x-7+\frac{41}{2x+3}$
Réponse finale au problème
$x-7+\frac{41}{2x+3}$