Exercice
$\frac{\left(16x^3+16x^2+7x+3\right)}{4x+3}$
Solution étape par étape
1
Diviser $16x^3+16x^2+7x+3$ par $4x+3$
$\begin{array}{l}\phantom{\phantom{;}4x\phantom{;}+3;}{\phantom{;}4x^{2}+x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}4x\phantom{;}+3\overline{\smash{)}\phantom{;}16x^{3}+16x^{2}+7x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}4x\phantom{;}+3;}\underline{-16x^{3}-12x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-16x^{3}-12x^{2};}\phantom{;}4x^{2}+7x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}4x\phantom{;}+3-;x^n;}\underline{-4x^{2}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{;-4x^{2}-3x\phantom{;}-;x^n;}\phantom{;}4x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}4x\phantom{;}+3-;x^n-;x^n;}\underline{-4x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;;-4x\phantom{;}-3\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Réponse finale au problème
$4x^{2}+x+1$