Final answer to the problem
$y=\left(x+\frac{1}{2}\right)^2-\frac{13}{4}$
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Apply the formula: $x^2+x+c$$=x^2+x+c+\frac{1}{4}-\frac{1}{4}$, where $c=-3$
$y=x^2+x-3+\frac{1}{4}-\frac{1}{4}$
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$y=x^2+x-3+\frac{1}{4}-\frac{1}{4}$
Learn how to solve equations problems step by step online. Solve the equation y=x^2+x+-3. Apply the formula: x^2+x+c=x^2+x+c+\frac{1}{4}-\frac{1}{4}, where c=-3. Apply the formula: x^2+x+c+f+g=\left(x+\sqrt{f}\right)^2+c+g, where c=-3, f=\frac{1}{4}, g=-\frac{1}{4} and x^2+x=x^2+x-3+\frac{1}{4}-\frac{1}{4}. Apply the formula: a^b=a^b, where a=\frac{1}{4}, b=\frac{1}{2} and a^b=\sqrt{\frac{1}{4}}. Apply the formula: \frac{a}{b}+c=\frac{a+cb}{b}, where a/b+c=\left(x+\frac{1}{2}\right)^2-3-\frac{1}{4}, a=-1, b=4, c=-3 and a/b=-\frac{1}{4}.
Final answer to the problem
$y=\left(x+\frac{1}{2}\right)^2-\frac{13}{4}$
