Solve the inequality $x^2-3x-10<0$

Step-by-step Solution

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Final answer to the problem

$x<5$
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Step-by-step Solution

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Apply the formula: $x+a+b<c$$=x+b<c-a$, where $a=-10$, $b=-3x$, $c=0$ and $x=x^2$

$x^2-3x<0+10$

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$x^2-3x<0+10$

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Learn how to solve simplification des fractions algébriques problems step by step online. Solve the inequality x^2-3x+-10<0. Apply the formula: x+a+b<c=x+b<c-a, where a=-10, b=-3x, c=0 and x=x^2. Apply the formula: a+b=a+b, where a=0, b=10 and a+b=0+10. Apply the formula: x^2+bx=x^2+bx+\left(\frac{b}{2}\right)^2-\left(\frac{b}{2}\right)^2, where b=-3, bx=-3x and x^2+bx=x^2-3x. Apply the formula: x^2+bx+f+g=\left(x+\sqrt{f}sign\left(b\right)\right)^2+g, where b=-3, bx=-3x, f=\frac{9}{4}, g=- \frac{9}{4} and x^2+bx=x^2-3x+\frac{9}{4}- \frac{9}{4}.

Final answer to the problem

$x<5$

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Plotting: $x<5$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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