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Apply the formula: $x+a=b$$\to x=b-a$, where $a=7$, $b=9$, $x+a=b=7+\sqrt[3]{5x-2}=9$, $x=\sqrt[3]{5x-2}$ and $x+a=7+\sqrt[3]{5x-2}$
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$\sqrt[3]{5x-2}=9-7$
Learn how to solve les limites de l'infini problems step by step online. Solve the equation with radicals 7+(5x-2)^(1/3)=9. Apply the formula: x+a=b\to x=b-a, where a=7, b=9, x+a=b=7+\sqrt[3]{5x-2}=9, x=\sqrt[3]{5x-2} and x+a=7+\sqrt[3]{5x-2}. Apply the formula: a+b=a+b, where a=9, b=-7 and a+b=9-7. Apply the formula: x^a=b\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}, where a=\frac{1}{3}, b=2, x^a=b=\sqrt[3]{5x-2}=2, x=5x-2 and x^a=\sqrt[3]{5x-2}. Apply the formula: x+a=b\to x=b-a, where a=-2, b=8, x+a=b=5x-2=8, x=5x and x+a=5x-2.
