Solve the equation with radicals $2x^{-2}-7x^{-1}-15=0$

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Final answer to the problem

$x=-\frac{2}{3},\:x=\frac{1}{5}$
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Apply the formula: $x+a=b$$\to x=b-a$, where $a=-7x^{-1}-15$, $b=0$, $x+a=b=2x^{-2}-7x^{-1}-15=0$, $x=2x^{-2}$ and $x+a=2x^{-2}-7x^{-1}-15$

$2x^{-2}=-\left(-7x^{-1}-15\right)$

Learn how to solve equations et fonctions radicales problems step by step online.

$2x^{-2}=-\left(-7x^{-1}-15\right)$

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Learn how to solve equations et fonctions radicales problems step by step online. Solve the equation with radicals 2x^(-2)-7x^(-1)+-15=0. Apply the formula: x+a=b\to x=b-a, where a=-7x^{-1}-15, b=0, x+a=b=2x^{-2}-7x^{-1}-15=0, x=2x^{-2} and x+a=2x^{-2}-7x^{-1}-15. Apply the formula: -\left(a+b\right)=-a-b, where a=-7x^{-1}, b=-15, -1.0=-1 and a+b=-7x^{-1}-15. Apply the formula: x^a=\frac{1}{x^{\left|a\right|}}. Move everything to the left hand side of the equation.

Final answer to the problem

$x=-\frac{2}{3},\:x=\frac{1}{5}$

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Function Plot

Plotting: $2x^{-2}-7x^{-1}-15$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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