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Solve the exponential equation $2^{\left(6x+7\right)}=\left(\frac{1}{8}\right)^{\left(1-5x\right)}$

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 Solution

 Videos

Solving exponential equations using exponent properties | High School Math | Khan Academy

https://www.youtube.com/watch?v=etl9KKf6se0

Tutorial - Solving a rational Equation ex1, 1/4 - x = x/8

https://www.youtube.com/watch?v=dnJbxTPp9V0

Algebra 2 - Solve an equation to factor by converting to exponential form logx (5x) = 2

https://www.youtube.com/watch?v=vD-gS0AaAdU

Tutorial - Solving an equation using factoring, 4x^2 - 5x + 1 = 0

https://www.youtube.com/watch?v=Ug_vC_Wf25U

Algebra 2 - Learning to solve rational equations in math class ((x+3)/(x‐2)) + (5/(x^2‐4)) = 1

https://www.youtube.com/watch?v=y8p0Tpn3BcI

Algebra 2 - converting between logarithmic and exponential form 15^3 = 3375, log125 (5) = 1/3

https://www.youtube.com/watch?v=u-vlkoXUrFg

 Function Plot

Plotting: $2^{\left(6x+7\right)}-\left(\frac{1}{8}\right)^{\left(1-5x\right)}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Equations exponentielles

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