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Apply the formula: $cx^a=b$$\to \left(cx^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}$, where $a=\frac{1}{3}$, $x^ac=b=2\sqrt[3]{7b-1}=-4$, $b=-4$, $c=2$, $x=7b-1$, $x^a=\sqrt[3]{7b-1}$ and $x^ac=2\sqrt[3]{7b-1}$
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$\left(2\sqrt[3]{7b-1}\right)^3=-64$
Learn how to solve problems step by step online. Solve the equation with radicals 2(7b-1)^(1/3)=-4. Apply the formula: cx^a=b\to \left(cx^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}, where a=\frac{1}{3}, x^ac=b=2\sqrt[3]{7b-1}=-4, b=-4, c=2, x=7b-1, x^a=\sqrt[3]{7b-1} and x^ac=2\sqrt[3]{7b-1}. Apply the formula: \left(ab\right)^n=a^nb^n, where a=2, b=\sqrt[3]{7b-1} and n=3. Apply the formula: ax=b\to \frac{ax}{a}=\frac{b}{a}, where a=8, b=-64 and x=7b-1. Apply the formula: x+a=b\to x=b-a, where a=-1, b=-8, x+a=b=7b-1=-8, x=7b and x+a=7b-1.
