$\frac{14a^3b^4}{-2ab^2}$

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Final answer to the problem

$-7a^{2}b^{2}$
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Step-by-step Solution

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Apply the formula: $\frac{a^n}{a}$$=a^{\left(n-1\right)}$, where $a^n/a=\frac{14a^3b^4}{-2ab^2}$, $a^n=a^3$ and $n=3$

$\frac{14a^{2}b^4}{-2b^2}$

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$\frac{14a^{2}b^4}{-2b^2}$

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Learn how to solve quotient des pouvoirs problems step by step online. (14a^3b^4)/(-2ab^2). Apply the formula: \frac{a^n}{a}=a^{\left(n-1\right)}, where a^n/a=\frac{14a^3b^4}{-2ab^2}, a^n=a^3 and n=3. Apply the formula: \frac{a^m}{a^n}=a^{\left(m-n\right)}, where a^n=b^2, a^m=b^4, a=b, a^m/a^n=\frac{14a^{2}b^4}{-2b^2}, m=4 and n=2. Apply the formula: \frac{ab}{c}=\frac{a}{c}b, where ab=14a^{2}b^{2}, a=14, b=a^{2}b^{2}, c=-2 and ab/c=\frac{14a^{2}b^{2}}{-2}.

Final answer to the problem

$-7a^{2}b^{2}$

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Plotting: $-7a^{2}b^{2}$

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1
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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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