Final answer to the problem
$\frac{27}{5}a^7$
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1
Apply the formula: $\frac{a}{a}$$=1$, where $a=c^8$ and $a/a=\frac{-108a^7c^8}{-20c^8}$
$\frac{-108a^7}{-20}$
2
Apply the formula: $\frac{ab}{c}$$=\frac{a}{c}b$, where $ab=-108a^7$, $a=-108$, $b=a^7$, $c=-20$ and $ab/c=\frac{-108a^7}{-20}$
$\frac{27}{5}a^7$
Final answer to the problem
$\frac{27}{5}a^7$
