$\lim_{x\to\infty }\left(\frac{e^x}{2^x}\right)$

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Final answer to the problem

$\infty $
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Step-by-step Solution

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Apply the formula: $\frac{a^n}{b^n}$$=\left(\frac{a}{b}\right)^n$, where $a^n=e^x$, $a=e$, $b=2$, $b^n=2^x$, $a^n/b^n=\frac{e^x}{2^x}$ and $n=x$

$\lim_{x\to\infty }\left(\left(\frac{e}{2}\right)^x\right)$

Learn how to solve les limites de l'infini problems step by step online.

$\lim_{x\to\infty }\left(\left(\frac{e}{2}\right)^x\right)$

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Learn how to solve les limites de l'infini problems step by step online. (x)->(infinity)lim((e^x)/(2^x)). Apply the formula: \frac{a^n}{b^n}=\left(\frac{a}{b}\right)^n, where a^n=e^x, a=e, b=2, b^n=2^x, a^n/b^n=\frac{e^x}{2^x} and n=x. Apply the formula: \lim_{x\to c}\left(a^b\right)={\left(\lim_{x\to c}\left(a\right)\right)}^{\lim_{x\to c}\left(b\right)}, where a=\frac{e}{2}, b=x and c=\infty . Apply the formula: \lim_{x\to c}\left(a\right)=a, where a=\frac{e}{2} and c=\infty . Evaluate the limit \lim_{x\to\infty }\left(x\right) by replacing all occurrences of x by \infty .

Final answer to the problem

$\infty $

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Function Plot

Plotting: $\frac{e^x}{2^x}$

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1
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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