$\frac{d}{dx}\left(\ln\left(xy\right)=e^{xy}\right)$

Step-by-step Solution

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Final answer to the problem

$y^{\prime}=\frac{-y}{x}$
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Step-by-step Solution

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1

Apply the formula: $\frac{d}{dx}\left(a=b\right)$$=\frac{d}{dx}\left(a\right)=\frac{d}{dx}\left(b\right)$, where $a=\ln\left(xy\right)$ and $b=e^{xy}$

$\frac{d}{dx}\left(\ln\left(xy\right)\right)=\frac{d}{dx}\left(e^{xy}\right)$
2

Apply the formula: $\frac{d}{dx}\left(\ln\left(x\right)\right)$$=\frac{1}{x}\frac{d}{dx}\left(x\right)$

$\frac{1}{xy}\frac{d}{dx}\left(xy\right)=\frac{d}{dx}\left(e^{xy}\right)$
3

Apply the formula: $\frac{d}{dx}\left(ab\right)$$=\frac{d}{dx}\left(a\right)b+a\frac{d}{dx}\left(b\right)$, where $d/dx=\frac{d}{dx}$, $ab=xy$, $a=x$, $b=y$ and $d/dx?ab=\frac{d}{dx}\left(xy\right)$

$\frac{1}{xy}\left(\frac{d}{dx}\left(x\right)y+x\frac{d}{dx}\left(y\right)\right)=\frac{d}{dx}\left(e^{xy}\right)$
4

Apply the formula: $\frac{d}{dx}\left(x\right)$$=1$

$\frac{1}{xy}\left(y+xy^{\prime}\right)=\frac{d}{dx}\left(e^{xy}\right)$
5

Apply the formula: $\frac{d}{dx}\left(e^x\right)$$=e^x\frac{d}{dx}\left(x\right)$, where $x=xy$

$\frac{1}{xy}\left(y+xy^{\prime}\right)=e^{xy}\frac{d}{dx}\left(xy\right)$
6

Apply the formula: $\frac{d}{dx}\left(ab\right)$$=\frac{d}{dx}\left(a\right)b+a\frac{d}{dx}\left(b\right)$, where $d/dx=\frac{d}{dx}$, $ab=xy$, $a=x$, $b=y$ and $d/dx?ab=\frac{d}{dx}\left(xy\right)$

$\frac{1}{xy}\left(y+xy^{\prime}\right)=e^{xy}\left(\frac{d}{dx}\left(x\right)y+x\frac{d}{dx}\left(y\right)\right)$
7

Apply the formula: $\frac{d}{dx}\left(x\right)$$=1$, where $x=y$

$\frac{1}{xy}\left(y+xy^{\prime}\right)=e^{xy}\left(y+xy^{\prime}\right)$
8

Apply the formula: $a\frac{b}{c}=f$$\to ab=fc$, where $a=y+xy^{\prime}$, $b=1$, $c=xy$ and $f=e^{xy}\left(y+xy^{\prime}\right)$

$y+xy^{\prime}=e^{xy}\left(y+xy^{\prime}\right)xy$
9

Group the terms of the equation by moving the terms that have the variable $y^{\prime}$ to the left side, and those that do not have it to the right side

$xy^{\prime}-e^{xy}\left(y+xy^{\prime}\right)xy=-y$
10

Move everything to the left hand side of the equation

$xy^{\prime}-e^{xy}\left(y+xy^{\prime}\right)xy+y=0$
11

Apply the formula: $a\left(b+c\right)+b+c$$=\left(b+c\right)\left(a+1\right)$, where $a=-e^{xy}xy$, $b=xy^{\prime}$, $c=y$ and $b+c=y+xy^{\prime}$

$\left(xy^{\prime}+y\right)\left(-e^{xy}xy+1\right)=0$
12

Break the equation in $2$ factors and set each factor equal to zero, to obtain simpler equations

$xy^{\prime}+y=0,\:-e^{xy}xy+1=0$
13

Solve the equation ($1$)

$xy^{\prime}+y=0$
14

Apply the formula: $x+a=b$$\to x=b-a$, where $a=y$, $b=0$, $x+a=b=xy^{\prime}+y=0$, $x=xy^{\prime}$ and $x+a=xy^{\prime}+y$

$xy^{\prime}=-y$
15

Apply the formula: $ax=b$$\to x=\frac{b}{a}$, where $a=x$, $b=-y$ and $x=y^{\prime}$

$y^{\prime}=\frac{-y}{x}$
16

Solve the equation ($2$)

$-e^{xy}xy+1=0$
17

This equation $-e^{xy}xy+1=0$ has no solutions in the real plane

$No solution$
18

The solution of the equation is

$y^{\prime}=\frac{-y}{x}$

Final answer to the problem

$y^{\prime}=\frac{-y}{x}$

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Function Plot

Plotting: $y^{\prime}=\frac{-y}{x}$

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1
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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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