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$\frac{1-\sin\left(x\right)}{\cos\left(x\right)}=\frac{\cos\left(x\right)}{1+\sin\left(x\right)}$

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Solution

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Videos

Proof the identity sin(x)^2 = 1 - cos(x)^2

https://www.youtube.com/watch?v=g7eVgtmQ7Dk

Integral de sen x entre 1 + cos x , completando derivada, forma dv/v

https://www.youtube.com/watch?v=xJvnQ3sAr-g

72. Límite trigonométrico: 1 - cos x entre x, racionalizando | Límite

https://www.youtube.com/watch?v=0qReyJTZnm0

Integral de dx entre 1 + cos x , multiplicando por conjugado y aplicando identidades

https://www.youtube.com/watch?v=ZepYdR310Sk

73. Límite trigonométrico: 1 - cos 4x entre x | Límite

https://www.youtube.com/watch?v=M-iaNPTAwdM

79. Límite trigonométrico con senos y cosenos: x sen x entre 1 - cos 2x | Límite

https://www.youtube.com/watch?v=dwSHXaDOzv8

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Similar Problems Solved

$\frac{1-sin\left(x\right)}{cos\left(x\right)}=\frac{cos\left(x\right)}{1+sin\left(x\right)}$

$\frac{1-\sin\:\left(x\right)}{\cos\:\left(x\right)}=\frac{\cos\:\left(x\right)}{1+\sin\:\left(x\right)}$

$\sec\:\left(x\right)-\tan\:\left(x\right)=\frac{\cos\:\left(x\right)}{1+\sin\:\left(x\right)}$

$\frac{1}{1-sin\left(x\right)}-\frac{1}{1+\sin\left(x\right)}=2\tan\left(x\right)sec\left(x\right)$

$tan\left(x\right)+cot\left(x\right)=sec\left(x\right)cosec\left(x\right)$

$\frac{1+\cos2x}{\sin2x}=\cot x$

$sec\left(x\right)-tan\left(x\right)sin\left(x\right)=\frac{1}{sec\left(x\right)}$

Main Topic: Identités trigonométriques

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See formulas (1)

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